10B【信标1由号=a得2线=a(a十1),当n-1时,由2a=a十a,得a,■1.当n≥2时,由25,=a+a.两式相减得2a。=a一a2-1十2S.-1m4.1+0。-11a,-4.1,整理得a,十a,1=(an十am-1)(a,一a。-1),因a,十a,1>0,故a,-ar1=1(m≥2).于是数列a}是首项a1=1,公差d=1的等差数列,故a,=a+(n一1)d=H,即①错误;S,1一2m)ata-2-(2m-1)1+2mD=2m-22@正确器一[n2]小工[+分++清-]-中音即16<6,④E,(1+京202202示),0错误故选B1